Target Test Prep Sample GRE Data Interpretation Problem
Food Item |
Serving size |
Servings per container |
Calories per serving |
PDV Dietary Fiber per serving |
PDV Saturated Fat per serving |
Peanut Butter |
2 Tbsp |
14 |
190 |
7% |
12% |
Soup |
1 cup |
2 |
250 |
4% |
30% |
The table shows two certain food items, peanut butter and soup. It shows their serving sizes, servings per container, calories per serving, percent of daily value (PDV) of dietary fiber per serving, and percent of daily value (PDV) of saturated fat per serving.
Erica loves peanut butter in her soup. At lunch, she adds one tablespoon of peanut butter to the entire can of soup as she is warming it. Assuming that she will eat the entire can of soup, by what percent has she increased the caloric value of her lunch soup?
Solution:
We first determine that she will consume the entire can of soup, which contains two servings. Each serving has 250 calories, so the soup alone yields 500 calories.
Now we determine the number of calories in one tablespoon of peanut butter. A tablespoon of peanut butter is half a serving, so she will add $\frac{190}{2}=95$ calories to the soup. Thus, her final concoction will contain (500 + 95) = 595 calories.
We need to calculate the percent increase of her calories by adding the peanut butter.
$\begin{array}{c}\Rightarrow \%\text{change =}\left(\frac{Final\text{\hspace{0.17em}}Value-Initial\text{\hspace{0.17em}}Value}{Initial\text{\hspace{0.17em}}Value}\right)\times 100\\ \Rightarrow \%\text{change}=\frac{595-500}{500}\times 100\%\\ \Rightarrow \%\text{change}=\frac{95}{500}\times 100\%\\ \Rightarrow \%\text{change}=19\%\end{array}$
This is a positive value, so the percent change is an increase of 19%.